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3x^2-93x-378=0
a = 3; b = -93; c = -378;
Δ = b2-4ac
Δ = -932-4·3·(-378)
Δ = 13185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13185}=\sqrt{9*1465}=\sqrt{9}*\sqrt{1465}=3\sqrt{1465}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-93)-3\sqrt{1465}}{2*3}=\frac{93-3\sqrt{1465}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-93)+3\sqrt{1465}}{2*3}=\frac{93+3\sqrt{1465}}{6} $
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